C# Класс Tortuga.Chain.Access.AccessObjectName

Represents an object in Acces (e.g. table, view, procedure)

Открытые свойства

Свойство	Тип	Описание
Empty	AccessObjectName

Метод	Описание
AccessObjectName ( string name ) : System	Initializes a new instance of the AccessObjectName struct.
Equals ( AccessObjectName other ) : bool	Returns true if the two objects are equal. This is a case-insensitive comparison.
Equals ( object obj ) : bool	Determines whether the specified object, is equal to this instance. This is a case-insensitive comparison.
GetHashCode ( ) : int	Returns a hash code for this instance. This is a case-insensitive comparison.
ToQuotedString ( ) : string	To the quoted string.
ToString ( ) : string	Returns a string that represents this instance.
operator ( ) : bool	Implements the operator !=. This is a case-insensitive comparison.

Метод	Описание
Normalize ( string value ) : string

Initializes a new instance of the AccessObjectName struct.

public AccessObjectName ( string name ) : System
name	string	The name.
Результат	System

Returns true if the two objects are equal.

This is a case-insensitive comparison.

public Equals ( AccessObjectName other ) : bool
other	AccessObjectName
Результат	bool

Determines whether the specified object, is equal to this instance.

This is a case-insensitive comparison.

public Equals ( object obj ) : bool
obj	object	The to compare with this instance.
Результат	bool

Returns a hash code for this instance.

This is a case-insensitive comparison.

public GetHashCode ( ) : int
Результат	int

To the quoted string.

public ToQuotedString ( ) : string
Результат	string

Returns a string that represents this instance.

public ToString ( ) : string
Результат	string

Implements the operator !=.

This is a case-insensitive comparison.

public static operator ( ) : bool
Результат	bool

An empty schema/name pair

public static AccessObjectName,Tortuga.Chain.Access Empty
Результат	AccessObjectName