C# Класс Common.Logging.Simple.DebugOutLogger

Наследование: Common.Logging.Simple.AbstractSimpleLogger

Открытые методы

Метод	Описание
DebugOutLogger ( string logName, LogLevel logLevel, bool showLevel, bool showDateTime, bool showLogName, string dateTimeFormat ) : System	Creates and initializes a logger that writes messages to System.Diagnostics.Debug.

Метод	Описание
WriteInternal ( LogLevel level, object message, Exception e ) : void	Do the actual logging by constructing the log message using a StringBuilder then sending the output to Debug >> Out" />.

Creates and initializes a logger that writes messages to System.Diagnostics.Debug.

public DebugOutLogger ( string logName, LogLevel logLevel, bool showLevel, bool showDateTime, bool showLogName, string dateTimeFormat ) : System
logName	string	The key, usually type key of the calling class, of the logger.
logLevel	LogLevel	The current logging threshold. Messages received that are beneath this threshold will not be logged.
showLevel	bool	Include the current log level in the log message.
showDateTime	bool	Include the current time in the log message.
showLogName	bool	Include the instance key in the log message.
dateTimeFormat	string	The date and time format to use in the log message.
Результат	System

Do the actual logging by constructing the log message using a StringBuilder then sending the output to Debug >> Out" />.

protected WriteInternal ( LogLevel level, object message, Exception e ) : void
level	LogLevel	The of the message.
message	object	The log message.
e	System.Exception	An optional associated with the message.
Результат	void