Свойство | Тип | Описание |
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Метод | Описание | |
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BrentSearch ( double>.Func |
Constructs a new Brent search algorithm.
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Find ( double value ) : bool |
Attempts to find a value in the interval [a;b]
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Find ( double>.Func |
Finds a value of a function in the interval [a;b]
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FindRoot ( ) : bool |
Attempts to find a root in the interval [a;b]
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FindRoot ( double>.Func |
Finds the root of a function in the interval [a;b]
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Maximize ( ) : bool |
Finds the maximum of the function in the interval [a;b]
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Maximize ( double>.Func |
Finds the maximum of a function in the interval [a;b]
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Minimize ( ) : bool |
Finds the minimum of the function in the interval [a;b]
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Minimize ( double>.Func |
Finds the minimum of a function in the interval [a;b]
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public BrentSearch ( double>.Func |
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function | double>.Func | The function to be searched. |
a | double | Start of search region. |
b | double | End of search region. |
Результат | System |
public static Find ( double>.Func |
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function | double>.Func | The function to have its root computed. |
value | double | The value to be looked for in the function. |
lowerBound | double | Start of search region. |
upperBound | double | End of search region. |
tol | double | The tolerance for determining the solution. |
Результат | double |
public static FindRoot ( double>.Func |
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function | double>.Func | The function to have its root computed. |
lowerBound | double | Start of search region. |
upperBound | double | End of search region. |
tol | double | The tolerance for determining the solution. |
Результат | double |
public static Maximize ( double>.Func |
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function | double>.Func | The function to be maximized. |
lowerBound | double | Start of search region. |
upperBound | double | End of search region. |
tol | double | The tolerance for determining the solution. |
Результат | double |
public static Minimize ( double>.Func |
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function | double>.Func | The function to be minimized. |
lowerBound | double | Start of search region. |
upperBound | double | End of search region. |
tol | double | The tolerance for determining the solution. |
Результат | double |