C# Class Scimark_Csharp_Android.MonteCarlo

Estimate Pi by approximating the area of a circle. How: generate N random numbers in the unit square, (0,0) to (1,1) and see how are within a radius of 1 or less, i.e.

   sqrt(x^2 + y^2) < r 

since the radius is 1.0, we can square both sides and avoid a sqrt() computation:

 x^2 + y^2 <= 1.0 

this area under the curve is (Pi * r^2)/ 4.0, and the area of the unit of square is 1.0, so Pi can be approximated by

 # points with x^2+y^2 < 1 Pi =~ 		--------------------------  * 4.0 total # points